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Validating a leap year

validating a leap year-6

[1-9] # 01-09 or 1-9 | # .1[012] # 10,11,12 ) # end of group #2 / # follow by a "/" ( # start of group #3 (19|20)\\d\\d # 19[0-9][0-9] or 20[0-9][0-9] ) # end of group #3 The above regular expression is used to validate the date format in “dd/mm/yyyy”, you can easy customize to suit your need.

validating a leap year-35

Do they test edge cases including February 29 and December 31? Well really, it applies to just about any code a developer might write, and quite a lot of it may end up running in the Azure cloud!Basically need to validate a Reg Ex (date) of years between 19.The days cannot exceed the maximum month days; (ie.These are just the big stories that made news headlines.I'm sure thousands more occurred with varying degrees of impact and noticeability.Stories from yesteryear like this one remind me of the real-world dangers of software glitches.

Considering the recent widespread adoption of IOT and its intersection with cloud computing, we should all be on high alert.

“333/2/2008”, “29/02/200a” – day is invalid, year is invalid 7.

“29/a/2008”, “a/02/2008” – month is invalid, day is invalid 6.

i need to get it to input the date as so: mm/dd/yyyy and then output the date as so: February 29, 2004 is a date in a leap year.

I have 3 drop downs one for month one for year and one for date.

I think I have way to much logic here but not sure how to resolve. public class Regex Validator { //class variables private String DATE_REGEX = "^((19|20)\\d\\d)-(0?